SSAT Math Question 627: Answer and Explanation
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Question: 627
8. If m is an even integer, n is an odd integer, and p is the product of m and n, which of the following is always true?
- A. p is a fraction.
- B. p is an odd integer.
- C. p is divisible by 2.
- D. p is between m and n.
Correct Answer: C
Explanation:
Try Plugging In values that satisfy the question stem, and eliminate choices. It may be necessary to Plug In twice on must be true or always true questions. If m is an even number, let m = 2, and let n = 3 since it must be an odd integer. If p is the product of m and n, then p = (2)(3) = 6. Now check the choices. Eliminate (A) because p is not a fraction. Eliminate (B) as well since p is not an odd integer. Keep (C) because 6 is divisible by 2. 6 is not between 2 and 3, so eliminate (D). Finally, keep (E) because 6 is greater than zero. Plug In again to compare the remaining choices. Perhaps keep one number the same, so n = 3, but make m = -2 instead of 2. Now p = (-2)(3) = -6. Choice (C) still works since -6 is divisible by 2, but (E) no longer works since p is less than zero. Since it is always true, the correct answer is (C).